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yuliyalimonova1
@yuliyalimonova1
July 2022
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(x^3+8\x-2)*(x^2-4+4\x^2-2x+4) пожалуйста)
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wolveren79
Точно не помню но вроде так
(x3+8/x-2)*(x2-4+4/x2-2x+4)=(x4/x+8/x-2)*((x4+4)/x2-2x3/x2)=(8x4/x-2)*((x4+4-2x3)/x2)=(8x4-2x)/x*(2x+4)/x2=
(6x3*(2x+4))/(x*x2)=(12x4+24x3)/x3=(x3(12x+24))/x3
x3 сокращаешь
получаешь
12x+24
0 votes
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Answers & Comments
(x3+8/x-2)*(x2-4+4/x2-2x+4)=(x4/x+8/x-2)*((x4+4)/x2-2x3/x2)=(8x4/x-2)*((x4+4-2x3)/x2)=(8x4-2x)/x*(2x+4)/x2=
(6x3*(2x+4))/(x*x2)=(12x4+24x3)/x3=(x3(12x+24))/x3
x3 сокращаешь
получаешь
12x+24