5/x+4/x-3=3;
3/x-3/x+4=1.
1) 5/x +4/(x -3)=3
5(x-3)+4x=3x(x-3)
3x^2-18x+15=0
D=16
x1=1
x2=5
2) 3/x - 3/(x+4)=1
3(x+4) -3x=x(x+4)
x^2+4x+12=0
D=64
x1=-6
x2=2
1)5/x+4/x-3=3 |*x
5+4-3x=3x
9=6x
x=1,5
2)3/x-3/x+4=1 |*x
3-3+4x=x
3x=0
x=0
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Verified answer
1) 5/x +4/(x -3)=3
5(x-3)+4x=3x(x-3)
3x^2-18x+15=0
D=16
x1=1
x2=5
2) 3/x - 3/(x+4)=1
3(x+4) -3x=x(x+4)
x^2+4x+12=0
D=64
x1=-6
x2=2
1)5/x+4/x-3=3 |*x
5+4-3x=3x
9=6x
x=1,5
2)3/x-3/x+4=1 |*x
3-3+4x=x
3x=0
x=0