x+5 x 50
___ + ___ = _______
x-5 x+5 x^2-25
Решить ур-е
x+5/x-5 + x/x+5= 50/ x^2-25
x+5/(x-5)(x+5) + x(X-5)(x+5) = 50/ (x-5)(x+5)
(x+5)^2+x(x-5)=50
x^2+10x+25+x^2-5x=50
2x^2+5x-25=0
D=25-200=-175<0
x^2+10*x+25+x*(x-5)=50, 2*x^2+5*x-25=0, D=25+200=225, x1=(-5-15)/4=-5, x2=(-5+15)/4=5/2.
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Answers & Comments
x+5/x-5 + x/x+5= 50/ x^2-25
x+5/(x-5)(x+5) + x(X-5)(x+5) = 50/ (x-5)(x+5)
(x+5)^2+x(x-5)=50
x^2+10x+25+x^2-5x=50
2x^2+5x-25=0
D=25-200=-175<0
x^2+10*x+25+x*(x-5)=50, 2*x^2+5*x-25=0, D=25+200=225, x1=(-5-15)/4=-5, x2=(-5+15)/4=5/2.