За правилом суммы(U+V)' = U'+V' :
(x^3+1/x)' = (x^3)' + (1/x)' = 3(x^2) - 1/(x^2)
Ответ: 3(x^2) - 1/(x^2)
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За правилом суммы(U+V)' = U'+V' :
(x^3+1/x)' = (x^3)' + (1/x)' = 3(x^2) - 1/(x^2)
Ответ: 3(x^2) - 1/(x^2)