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vadiksidorenkoVram
@vadiksidorenkoVram
July 2022
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x+6=x^2 x2+4=5x (x-3)(x+3)=-5x-13
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ТатМих
Verified answer
х+6=х²
x²-x-6=0
по теореме Виетта
x1+x2=1
x1*x2=-6
x1=-2
x1=3
2.
x
²+4=5x
x
²-5x+4=0
D=b
²-4ac
D=25-16=9
√D=3
x1=(5-3)/2=1
x2=(5+3)/2=4
3.
(x-3)(x+3)=-5x-13
x
²-9=-5x-13
x
²+5x-9+13=0
x
²+5x+4=0
D=b
²-4ac
D=25-16=9
√9=3
x1=(-5+3)/2=-1
x2=(-5-3)/2=-4
2 votes
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Answers & Comments
Verified answer
х+6=х²x²-x-6=0
по теореме Виетта
x1+x2=1
x1*x2=-6
x1=-2
x1=3
2.
x²+4=5x
x²-5x+4=0
D=b²-4ac
D=25-16=9
√D=3
x1=(5-3)/2=1
x2=(5+3)/2=4
3.
(x-3)(x+3)=-5x-13
x²-9=-5x-13
x²+5x-9+13=0
x²+5x+4=0
D=b²-4ac
D=25-16=9
√9=3
x1=(-5+3)/2=-1
x2=(-5-3)/2=-4