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dima678435
@dima678435
May 2022
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Для какой функции справедливо неравенство y (4) < y (1)?
А) y= √x
Б) y= x^2
В) y= -4√x
Г) y= -4/x
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romanovalesya1
А) √4=2>√1=1
Б) 4²=16>1²=1
В) -4*√4=-8<-4*√1=-4
Г) -4/4=-1>-4/1=-4.
Ответ: В).
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Vasily1975
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Answers & Comments
Б) 4²=16>1²=1
В) -4*√4=-8<-4*√1=-4
Г) -4/4=-1>-4/1=-4.
Ответ: В).
Verified answer
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