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anna199916123
@anna199916123
July 2021
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(x²+7x)(x²-25)≤0!!!!!!!!!!!!!!!!!!!
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Удачник66
Verified answer
(x^2 + 7x)(x^2 - 25) <= 0
x(x + 7)(x + 5)(x - 5) <= 0
По методу интервалов
x = [-7; -5] U [0; 5]
1 votes
Thanks 1
anna199916123
спасибо большое
Удачник66
пожалуйста большое
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Answers & Comments
Verified answer
(x^2 + 7x)(x^2 - 25) <= 0x(x + 7)(x + 5)(x - 5) <= 0
По методу интервалов
x = [-7; -5] U [0; 5]