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Maryashc
@Maryashc
July 2022
1
13
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найдите точку минимума функции y= (x^2+361)/x
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sedinalana
Verified answer
Y=(x²+361)/x=x+361/x
y`=1-361/x²=(x²-361)/x2
x²=361
x=-19 U x=19
+ _ +
--------------(-19)------------(19)-----------------
min
ymin=y(19)=38
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Answers & Comments
Verified answer
Y=(x²+361)/x=x+361/xy`=1-361/x²=(x²-361)/x2
x²=361
x=-19 U x=19
+ _ +
--------------(-19)------------(19)-----------------
min
ymin=y(19)=38