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мамасита17
@мамасита17
August 2022
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1. Найдите значение выражения (корень из 12 + 2 корень из 3)^2/10
2. Найдите корни уравнения x^2-6x-7=0
3. Сократите дробь (6x+3)^2-(6x-3)^2/x
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anmih
Verified answer
1) (√12+2√3)^(2) / 10 = (12+4√36+12) / 10 = (24+24) / 10 =
4.8
2)
x^2 -6x-7 = 0
D=36+28=64
x(1)=(6+8)/2=
7
x(2)=(6-8)/2=
-1
3) ...=(36x2+36x+9-36x2+36x-9) / x = 72x / x =
72
2 votes
Thanks 1
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Answers & Comments
Verified answer
1) (√12+2√3)^(2) / 10 = (12+4√36+12) / 10 = (24+24) / 10 = 4.82)
x^2 -6x-7 = 0
D=36+28=64
x(1)=(6+8)/2=7
x(2)=(6-8)/2=-1
3) ...=(36x2+36x+9-36x2+36x-9) / x = 72x / x = 72