Найдите значение выражения (x-9) : (x^2-18x+81)/(x+9)при x = 45. Created by vselemorin. algebra-ru

(x+9)при x = 45...

vselemorin @vselemorin

July 2022 2 23 Report

Найдите значение выражения
(x-9) : (x^2-18x+81)/(x+9)
при x = 45

Regent1828

Verified answer

$\displaystyle (x-9):\frac{x^{2}-18x+81}{x+9}=(x-9)*\frac{x+9}{(x-9)^{2}}=\frac{x+9}{x-9};$

при х = 45: $\displaystyle \frac{x+9}{x-9}= \frac{45+9}{45-9}= \frac{54}{36}= \frac{3}{2}=1,5$

48 votes Thanks 67

crdd

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$(x-9) : \frac{x^{2}-18x+81}{x+9} = (x-9) : \frac{(x-9)^{2}}{x+9} = \frac{(x-9)(x+9)}{(x-9)^{2}} = \frac{x+9}{x-9} \\ \\ x=45\\ \\ \frac{45+9}{45-9} = \frac{54}{36} =\frac{3}{2}$

42 votes Thanks 60

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