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KateSnape97
@KateSnape97
August 2022
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Определите критические точки функции f(x)=x3-9x. f(x)=-2/x
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mmb1
Verified answer
f(x)=x3-9x
f'=3x2-9=3x(x-3)
критические точки 0 3 точки экстремумов
. f(x)=-2/x
критическая точка х=0 - точка неопределенности
1 votes
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Answers & Comments
Verified answer
f(x)=x3-9xf'=3x2-9=3x(x-3)
критические точки 0 3 точки экстремумов
. f(x)=-2/x
критическая точка х=0 - точка неопределенности