Решение.
[tex]\displaystyle S=\int\limits_1^2\, x^2\, dx=\frac{x^3}{3}\ \Big|_1^2=\frac{2^3}{3}-\frac{1^3}{3}=\frac{8}{3}-\frac{1}{3}=\frac{7}{3}[/tex]
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Решение.
[tex]\displaystyle S=\int\limits_1^2\, x^2\, dx=\frac{x^3}{3}\ \Big|_1^2=\frac{2^3}{3}-\frac{1^3}{3}=\frac{8}{3}-\frac{1}{3}=\frac{7}{3}[/tex]