Вычислить предел: lim = 1-cos3x / x*sin2x Помогите решить
x→0
1-cos3x=2sin²3x/2
2sin²3x/2 2 * 3x/2*3x/2 18 x² 9
lim ----------------- = lim -------------------- = lim ----------- = ------
x sin2x x*2x 8x² 4
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1-cos3x=2sin²3x/2
2sin²3x/2 2 * 3x/2*3x/2 18 x² 9
lim ----------------- = lim -------------------- = lim ----------- = ------
x sin2x x*2x 8x² 4