x (x - 2) + 5 (x - 2) = 0
x² - 2x + 5x - 10 = 0
x² + 3x - 10 = 0
D = 3² - 4 · 1 · (-10) = 9 + 40 = 49
x = (- 3 ± √49) / 2 = (- 3 ± 7) / 2
x₁ = (- 3 - 7) / 2 = - 10/2 = - 5
x₂ = (- 3 + 7) / 2 = 4/2 = 2
Ответ: x₁ = - 5; x₂ = 2
Ответ:
..... Aahgb you can be used
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x (x - 2) + 5 (x - 2) = 0
x² - 2x + 5x - 10 = 0
x² + 3x - 10 = 0
D = 3² - 4 · 1 · (-10) = 9 + 40 = 49
x = (- 3 ± √49) / 2 = (- 3 ± 7) / 2
x₁ = (- 3 - 7) / 2 = - 10/2 = - 5
x₂ = (- 3 + 7) / 2 = 4/2 = 2
Ответ: x₁ = - 5; x₂ = 2
Ответ:
..... Aahgb you can be used