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tylyr
@tylyr
July 2022
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x(x^2+4x+4)=3(x+2) m
решите подробео
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massg
X(x+2)^2=3(x+2) x(x+2)^2-3(x+2)=0 (x+2)(x(x+2)-3)=0 (x+2)(x^2+2x-3)=0
(x+2)(x+3)(x-1)=0
x1= -2
x2= -3
x3= 1
1 votes
Thanks 3
prstal
-2 не подходит
massg
"заблуждаться может каждый, но упорствуют в заблуждении только _____" (4 -8 +4)
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Answers & Comments
(x+2)(x+3)(x-1)=0
x1= -2
x2= -3
x3= 1