50 БАЛЛОВ!!! Упростите выражение: x*x^2*x^3*...x^n/x*x^3*x^5...x^2n-1. Created by azhailmina. algebra-ru

x*x^3*x^5...x^2n-1...

December 2021 1 9 Report

50 БАЛЛОВ!!!
Упростите выражение:
x*x^2*x^3*...x^n/x*x^3*x^5...x^2n-1

Answers & Comments

ruslank1460

первую и вторую сумму находим как сумму первых n членов арифметической прогрессии (средний арифметический умножаем на их количество)

$\frac{x*x^2*x^3*...*x^n}{x*x^3*x^5*...*x^{2n-1}}=x^{1+2+3+...+n-(1+3+5+...+2n-1)}=x^{\frac{1+n}{2}*n-\frac{1+2n-1}{2}*n}=x^{\frac{1+n-2n}{2}*n}=\\=x^{\frac{(1-n)n}{2}}$

1 votes Thanks 1

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Answers & Comments

30 balov esse tragediya grazhdanskoj vojny

croooochnooo reshite pozhalujsta bolat reshil 20 zadach za kazhdyj pravilnyj

srednyaya vysota antarktidy vmeste s ledyanym pokrovom prevyshaet srednyuyu vysotu dru

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40 ballov kakie shodstva i razlichiya est v ekonomike kazahstana i drugih byvshi

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turist puteshestvoval po gorodu na metro na mashine i peshkom vyberite vernye vy

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