[tex]\left \{ {{x=y^2-2y} \atop {x+y=2}} \right.[/tex]

[tex]\left \{ {{x=2-y} \atop {2-y=y^2-2y}} \right.[/tex]

[tex]y^{2}[/tex]-2y+y-2=0

[tex]y^{2}[/tex]-y-2=0

D=[tex](-1)^{2}[/tex]-4*1*(-2)=1+8=9
[tex]x_{1}[/tex]=[tex]\frac{1+3}{2}[/tex]=2

[tex]x_{2}[/tex]=[tex]\frac{1-3}{2}=-1[/tex]

x+y=2, y=2-x

[tex]y_{1}[/tex]=2-2=0

[tex]y_{2}[/tex]=2+1=3

Ответ(2;0),(-1;3)