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alex3112
@alex3112
June 2022
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x+y=6
x^2-y^2=12 x-?
решите пожалуйста
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nastyakuznecov
Объединяем в систему:
x+y=6 и x^2-y^2=12;
x=6-y и (6-y)^2-y^2=12
x=6-y и 36-12y+y^2-y^2=12
x=6-y и -12y=12-36
x=6-y и 12y=24
x= -6 и y=12
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nastyamiusha
Y=6-x
x^2-(6-x)^2=12
x^2-36+12x-x^2=12
12x=48
x=4
y=6-4=2
0 votes
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Answers & Comments
x+y=6 и x^2-y^2=12;
x=6-y и (6-y)^2-y^2=12
x=6-y и 36-12y+y^2-y^2=12
x=6-y и -12y=12-36
x=6-y и 12y=24
x= -6 и y=12
x^2-(6-x)^2=12
x^2-36+12x-x^2=12
12x=48
x=4
y=6-4=2