y' = (x-10)^2+(x+1)*(2x-20)...

zaga12121212 @zaga12121212

July 2022 1 7 Report

y' = (x-10)^2+(x+1)*(2x-20)

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post60 $\frac{dy}{dx} =(x-10)^2+(x+1)(2x-20)\\ \\\int {y} \, dy =\int{(x^2-20x+100+2x^2+2x-20x-20)dx}\\ \\ \ y=\int{(3x^2-38x+80)}dx=x^3-19x^2+80x+C$

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