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Baltezar
@Baltezar
July 2022
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y=13x3-x2 в точке x0=1
Найдите производную функции
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русская25
Y=13x³ - x², x₀=1,
y'(x)=(13x³ - x²)'= 3*13x² - 2x=39x²-2x
y'(1)= 39*1² - 2*1 = 39 - 2 = 37.
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Answers & Comments
y'(x)=(13x³ - x²)'= 3*13x² - 2x=39x²-2x
y'(1)= 39*1² - 2*1 = 39 - 2 = 37.