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rai1505
@rai1505
July 2022
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y=1+ctg (2x-pi) help me pleas, good luck
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oganesbagoyan
Verified answer
У = 1 +ctq(2x -π) =1 +ctq(-(π-2x)) =1 -ctq(π -2x) =1 -ctq2x.
y(xo) = y(π/4) = 1 -ctq(2*π/4) =1 -ctqπ/2 =1 -0 =
1.
10 votes
Thanks 9
rai1505
y=1+ctg ( 2x - pi )в точке x°=-pi/4
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Verified answer
У = 1 +ctq(2x -π) =1 +ctq(-(π-2x)) =1 -ctq(π -2x) =1 -ctq2x.y(xo) = y(π/4) = 1 -ctq(2*π/4) =1 -ctqπ/2 =1 -0 =1.