y=1+ctg (2x-pi) help me pleas, good luck...

rai1505 @rai1505

July 2022 1 4 Report

y=1+ctg (2x-pi) help me pleas, good luck

Answers & Comments

oganesbagoyan

Verified answer

У = 1 +ctq(2x -π) =1 +ctq(-(π-2x)) =1 -ctq(π -2x) =1 -ctq2x.
y(xo) = y(π/4) = 1 -ctq(2*π/4) =1 -ctqπ/2 =1 -0 =1.

10 votes Thanks 9

rai1505 y=1+ctg ( 2x - pi )в точке x°=-pi/4

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