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uauarmrmrmmrmr
@uauarmrmrmmrmr
July 2023
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y^2+19y+52=0
решите по теореме Виета, пожалуйста.
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kaxanov1920
a-1,b-19,c-52
у=-19+-v19^2-4•1•52
2•1
у=-19+-v361-208
2
y=-19+-v153
2
y=-19+-3v17
2
y1=-19+3v17
2
y2=-19-3v17
2
Ответ:у1=15,6 у2=3,3
1 votes
Thanks 1
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Answers & Comments
у=-19+-v19^2-4•1•52
2•1
у=-19+-v361-208
2
y=-19+-v153
2
y=-19+-3v17
2
y1=-19+3v17
2
y2=-19-3v17
2
Ответ:у1=15,6 у2=3,3