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Freiderich
@Freiderich
August 2022
2
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Упростите выражения:
z^2+6z+9/z^3+27 : 3z+9/z^2-3z+9;
y^3-8/y-9 * y+3/y^2+2y+4.
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miron2077
Verified answer
!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
2 votes
Thanks 1
Freiderich
Спасибо
sedinalana
1
(z+3)²/(z+3)(z²-3z+9):3(z+3)/(z²-3z+9)=(z+3)/9z²-3z+9) *(z²-3z+9)/3(z+3)=
=1/3
2
(y-2)(y²+2y+4)/(y-9) *(y+3)/(y+2y+4)=(y-2)(y+3)/(y-9)=(y²+y-6)/(y-9)
0 votes
Thanks 0
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Answers & Comments
Verified answer
!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!(z+3)²/(z+3)(z²-3z+9):3(z+3)/(z²-3z+9)=(z+3)/9z²-3z+9) *(z²-3z+9)/3(z+3)=
=1/3
2
(y-2)(y²+2y+4)/(y-9) *(y+3)/(y+2y+4)=(y-2)(y+3)/(y-9)=(y²+y-6)/(y-9)