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ynifar
@ynifar
August 2022
1
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я нуждаюсь в вашей помощи
B4 во вложении
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Vas61
F'(x)=2·3x²/3-18=2x²-18
g'(x)=2·1/2√x=1/√x
f'(x)/g'(x)=(2x²-18)÷1/√x=2√x(x²-9)
2√x(x²-9)=0
√x=0 x=0
x²-9=0 x=-3 x=3
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Answers & Comments
g'(x)=2·1/2√x=1/√x
f'(x)/g'(x)=(2x²-18)÷1/√x=2√x(x²-9)
2√x(x²-9)=0
√x=0 x=0
x²-9=0 x=-3 x=3