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vala2000
@vala2000
October 2021
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Яка маса кисню об'ємом 67,2 л при н.у.?
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gandyuk
N(O2) = V : Vm= 67,2л : 22,4л/моль= 3 моль
m(O2) = n(O2) * M(O2) = 3 моль * 32г/моль= 96г
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Answers & Comments
m(O2) = n(O2) * M(O2) = 3 моль * 32г/моль= 96г