яка масова частка елемента оксигену в речовині CO2
M(CO2)=12+32=44
w(O)=32/44*100=73%
C+O2
12+2*16=44
32\44=8\11≈0,72
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Verified answer
M(CO2)=12+32=44
w(O)=32/44*100=73%
Verified answer
C+O2
12+2*16=44
32\44=8\11≈0,72