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skyvla
@skyvla
June 2022
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Який обьем ацитилена выделиться при пиролизе метана м=320г
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DarkChemist
2CH4 (t°)-> C2H2 + 3H2
m(CH4) = 320 (г)
n(CH4) = m / M = 320 / 16 = 20 (моль)
n(C2H2) = n(CH4) / 2 = 20 / 2 = 10 (моль)
V(C2H2) = Vm * n = 22,4 * 10 = 224 (л)
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Answers & Comments
m(CH4) = 320 (г)
n(CH4) = m / M = 320 / 16 = 20 (моль)
n(C2H2) = n(CH4) / 2 = 20 / 2 = 10 (моль)
V(C2H2) = Vm * n = 22,4 * 10 = 224 (л)