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kreek2012223
@kreek2012223
December 2021
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Який об`ем хлороводню (н.у) можна добути iз хлору об`емом 18м3 (н.у) в результатi реакцii з воднем
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mastermax
H2+Cl2=2HCl (кстати, при н.у. хлороводород - газ)
V(HCl)=V(Cl2)*2=36(м3)=36000(л)
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Answers & Comments
V(HCl)=V(Cl2)*2=36(м3)=36000(л)