m(C2H4) = 60 gV(C2H2) - ?
n(C2H4) = 60 g / 28 g / mol = 2.142 mol (к тысячным)
2.142 mol x mol
C2H4 = C2H2 + H2
1 mol 1 mol
1:2.142 = 1:x
x = 2.142
V(C2H2) = 2.142 mol * 22.4 l / mol = 47.9808 l = 48 l (к целым)
Ответ: 48 l .
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m(C2H4) = 60 g
V(C2H2) - ?
n(C2H4) = 60 g / 28 g / mol = 2.142 mol (к тысячным)
2.142 mol x mol
C2H4 = C2H2 + H2
1 mol 1 mol
1:2.142 = 1:x
x = 2.142
V(C2H2) = 2.142 mol * 22.4 l / mol = 47.9808 l = 48 l (к целым)
Ответ: 48 l .