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Juulisaa
@Juulisaa
August 2022
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Який об'єм займає 64 г метану?
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komz98
N = V/V(a). n = m/M. Значит, n(CH3)= 64/15=4,26 моль. Далее, V = n * V(a) = 4,26 * 22,4 = 95,424 (л).
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