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@098765423456
November 2021
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яку масу пропену необхідна для одержання 20г пропанолу,якщо масова частка виходу продукту становить 80%?
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Alexei78
Дано
m прак(C3H7OH) = 20 g
η = 80%
------------------------
m(C3H6)-?
m(C3H7OH) = 20*100% / 80% = 25 g
C3H6+H2O-->C3H7OH
M(C3H7OH) = 60 g/mol
n(C3H7OH) = m/M = 25/60 = 0.42 mol
n(C3H6) = n(C3H7OH) = 0.42 mol
M(C3H6) = 42 g/mol
m(C3H6) = n*M = 0.42 * 42 = 17.64г
ответ 17.64 г
1 votes
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Answers & Comments
m прак(C3H7OH) = 20 g
η = 80%
------------------------
m(C3H6)-?
m(C3H7OH) = 20*100% / 80% = 25 g
C3H6+H2O-->C3H7OH
M(C3H7OH) = 60 g/mol
n(C3H7OH) = m/M = 25/60 = 0.42 mol
n(C3H6) = n(C3H7OH) = 0.42 mol
M(C3H6) = 42 g/mol
m(C3H6) = n*M = 0.42 * 42 = 17.64г
ответ 17.64 г