найдите 2x-y/yесли 8^y=5 и 4^x=125. Created by Djasurxon. matematika-ru

yесли 8^y=5 и 4^x=125...

Света19999

Verified answer

У = log8(5) = (1/3)*log2(5)
x = log4(125) = (1/2)*3*log2(5) = (3/2)*log2(5)
Тогда: (2x-y)/y =
= ((2/3)*log2(5) - (3/2)*log2(5))/((3/2)*log2(5)) =
= (2/3)*(2/3) - 1 = 4/9 - 1 = -5/9
Ответ: -5/9.

1 votes Thanks 0

sedinalana

Verified answer

8^y=5
2^(3y)=5
3y=log(2)5
y=1/3*log(2)5
4^x=125
2^(2x)=125
2x=log(2)125
x=1/2*3*log(2)5=3/2*log(2)5
(2x-y)/x=2x/y-1=(2*3/2*log(2)5):(1/3*log(2)5-1=3log(2)5:1/3*log(2)5-1=9-1=8

1 votes Thanks 0

Света19999 а как вы получили (2х-у)/х = 2у/х-1?

Answers & Comments

Verified answer

Verified answer

c7bad7671c55dcc3a14274d3c65d90db

4 7 14 98 112

2d45239d25ad0af63307c0c7c309ee71

3)...

xyyzzx16najdite naimenshee znachenie xyz2

reshite sistemu uravneniya23d5aac163df6edba03643ca98e17c80 20682

srochno nuzhno sdelatf38fdd81616461e0259878f78e2354d2 81594

pomogite pozhalujsta srochno nuzhno sdelat9cf73255dc0077147d2ddae7e75eef1c 98515

srochno nuzhno sdelata713c4771402fc5e8d9b314fd9033bec 24235

vychislite pozhalujsta srochno nuzhnofba2de573924250a59030c418d5c4a6a 79842

рекомендуемые вопросы

Helpful Links

Helpful Social