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tanova9807
@tanova9807
July 2022
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y=e^xlu(2x-1) найдите производную функции срочно
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nKrynka
Решение
Y=e^xlu(2x-1)
y` = e^x * ln(2x - 1) + [2*(e^x)]/(2x - 1)
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Answers & Comments
Y=e^xlu(2x-1)
y` = e^x * ln(2x - 1) + [2*(e^x)]/(2x - 1)