y=sqrt3*x+sin2x [0;Pi]. Created by Aldiyar21. literatura-ru

y=sqrt3*x+sin2x [0;Pi]...

July 2022 1 3 Report

y=sqrt3*x+sin2x [0;Pi]

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MiSTiK5267 y=f(x0) + f'(x0)(x-x0)
f(x0) и f'(x0)
f(x0) = sin(3*пи/3-2пи/3) = sin(60) = sqrt(3)/2
f'(x0) = 3*cos(3*x0-2пи/3) = 3*cos(3*пи/3-2пи/3) = 3*cos(60) = 3/2

y=sqrt(3)/2 + ( x- пи/3)*3/2
y=(3/2)*x + sqrt(3)/2 - пи/2

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fx x5 nado najti promezhutok vozrastaniya

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