Ответ:
x = (-1)^k × π/6 + πk , k € Z
Объяснение:
y = x-2cosx
y ` = (x-2×cosx) ` = (x) ` - (2×cosx) ` = (x) ` - (2) ` × (cosx) + (2) × (cosx) ` = 1 - 2sinx
y ` = 0
1 - 2sinx = 0
-2sinx = -1
sinx = 1/2
x = (-1)^k × arcsin(1/2) + πk , k€ Z
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Ответ:
x = (-1)^k × π/6 + πk , k € Z
Объяснение:
y = x-2cosx
y ` = (x-2×cosx) ` = (x) ` - (2×cosx) ` = (x) ` - (2) ` × (cosx) + (2) × (cosx) ` = 1 - 2sinx
y ` = 0
1 - 2sinx = 0
-2sinx = -1
sinx = 1/2
x = (-1)^k × arcsin(1/2) + πk , k€ Z
x = (-1)^k × π/6 + πk , k € Z