yy´=1+x
y´=(1+x)/y
dy/dx = (1+x)/y
ydy=(1+x)dx
∫ydy=∫(1+x)dx
y²/2=x+x²
y²=2x+2x²
/y/=√(2x+2x²) + c
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yy´=1+x
y´=(1+x)/y
dy/dx = (1+x)/y
ydy=(1+x)dx
∫ydy=∫(1+x)dx
y²/2=x+x²
y²=2x+2x²
/y/=√(2x+2x²) + c