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mascamasa
@mascamasa
July 2022
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Задача
m (Cl2)-14.2 грамм
v (HCl)-?
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Answers & Comments
ppana3909
Н2+СL2= 2HCL
V=n/VM
n(Cl) = 14,2/70
n(Cl) = 0,2моль
n(HCl) = 0,2/1=x/2
n(HCl) = 0,4
V(HCl) =0,4*22,4=8,96дм3
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Answers & Comments
V=n/VM
n(Cl) = 14,2/70
n(Cl) = 0,2моль
n(HCl) = 0,2/1=x/2
n(HCl) = 0,4
V(HCl) =0,4*22,4=8,96дм3