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kirillovchin
@kirillovchin
August 2022
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Задача по химии
Дано:
М(вещества)=4,8г
М(СО2)=6,2г
М(Н2О)=5,4г
DH2=16
Найти x, y, z в химической формуле CxHyOz
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rozanigmatylina
X 6,2
C+O2=Co2 x=12x6,2/22,4=3,32г
12 22,4
x1 5,4
2H2+02=2H2O x1=4x5,4/36=0,6 m(o2)=4,8-(3,32+0,6)=0,88
4 36
3,32/12:0,6/1 :0,88/16=0,28:0,6 :0,055=0,28/0,055:0,6/0,055 :1=5,09:10,9:1=6:11;1
Mr(C6H11O)=99
Mr(CxHyOz)=16x2=32 n=3 6/3=2 11/3=3.6это примерно 4 С2H4O
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Answers & Comments
C+O2=Co2 x=12x6,2/22,4=3,32г
12 22,4
x1 5,4
2H2+02=2H2O x1=4x5,4/36=0,6 m(o2)=4,8-(3,32+0,6)=0,88
4 36
3,32/12:0,6/1 :0,88/16=0,28:0,6 :0,055=0,28/0,055:0,6/0,055 :1=5,09:10,9:1=6:11;1
Mr(C6H11O)=99
Mr(CxHyOz)=16x2=32 n=3 6/3=2 11/3=3.6это примерно 4 С2H4O