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fox364
@fox364
August 2022
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задача по химии
Zn+2HCl=ZnCl2+H2
m Zn =3.25 г
W HCl =10%
mHCl = ?
V H2 =?
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Answers & Comments
alvltrif
N(Zn)=3.25г:65г/моль=0.05моль
n(H2)=n(Zn)=0.05моль
V(H2)=0.05моль×22.4л/моль=1.12л
n(HCl)=2n(Zn)=0.1моль
m(р-на HCl)=0.1моль×36.5г/моль=3.65г
m(HCl)=3.65л×0.1=0.365г
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Answers & Comments
n(H2)=n(Zn)=0.05моль
V(H2)=0.05моль×22.4л/моль=1.12л
n(HCl)=2n(Zn)=0.1моль
m(р-на HCl)=0.1моль×36.5г/моль=3.65г
m(HCl)=3.65л×0.1=0.365г