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ender20383
@ender20383
July 2022
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Задача по химии
m p-p=300гр
w(NaQ)= 10 процентов
+300 гр соли-100гр воды
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Виктория0503
Verified answer
M(в-ва)1 = w*m(р-ра) = 300*0.1 = 30г
w = m(в-ва)1 + m(в-ва)2/m(р-ра) + m(воды) + m(соли)
w = (30 + 300)/(300+300-100) = 330/500 = 0.66 или 66%
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Answers & Comments
Verified answer
M(в-ва)1 = w*m(р-ра) = 300*0.1 = 30гw = m(в-ва)1 + m(в-ва)2/m(р-ра) + m(воды) + m(соли)
w = (30 + 300)/(300+300-100) = 330/500 = 0.66 или 66%