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Nasten4ek
@Nasten4ek
July 2022
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Задача.
С химией совсем все плохо, поэтому прошу решить полностью!
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ndambaeva
1. M(CxHy)=D(O2)*M(O2)=2.63*32=84g/mol
2. n(CO2)=40.32/22.4=1.8mol
m(CO2)=1.8mol*44g/mol=79.2g
mC=79.2*12/44=21.6g
nC=21.6/12=1.8mol
3. mH=32.4*2/18=3.6g
nH=3.6/1=3.6mol
4. найдем простейшую формулу
1.8:3.6=1:2
СН2
n(CH2)=84
n(12+2)=84
14n=84
n=6
C6H12-гексен или циклогексан
2 votes
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Nasten4ek
Спасибо!
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Answers & Comments
2. n(CO2)=40.32/22.4=1.8mol
m(CO2)=1.8mol*44g/mol=79.2g
mC=79.2*12/44=21.6g
nC=21.6/12=1.8mol
3. mH=32.4*2/18=3.6g
nH=3.6/1=3.6mol
4. найдем простейшую формулу
1.8:3.6=1:2
СН2
n(CH2)=84
n(12+2)=84
14n=84
n=6
C6H12-гексен или циклогексан