дано
m(CH2CL-CHCL-CH3) = 60 g
--------------------------------
m(CH2=CH-CH3)-?
X 60 g
CH2=CH-CH3+CL2-->CH2CL-CHCL-CH3
42 113
M(CH2=CH-CH3) = 42 g/mol
M(CH2CL-CHCL-CH3) =113 g/mol
X / 42 = 60 / 113
X = 42*60 / 113 = 22.3 g
ответ 22.3 г
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Verified answer
дано
m(CH2CL-CHCL-CH3) = 60 g
--------------------------------
m(CH2=CH-CH3)-?
X 60 g
CH2=CH-CH3+CL2-->CH2CL-CHCL-CH3
42 113
M(CH2=CH-CH3) = 42 g/mol
M(CH2CL-CHCL-CH3) =113 g/mol
X / 42 = 60 / 113
X = 42*60 / 113 = 22.3 g
ответ 22.3 г