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Beckinsale1333
@Beckinsale1333
September 2021
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Задачи по химии
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СофиРене
Задача 2. w(Fe)=Ar(Fe)/mr(FeO)=56/56+16=56/72=0.78=78%. w(Fe)=2Ar(Fe)/mr(Fe2O3)=2*56/2*56+16*3=112/160=0.70=70%. Ответ:Fe больше в FeO.
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