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valery00
@valery00
October 2021
1
15
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задачка,срочно!!!!!!!!!!!!!
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Vadim200129
R2 b R3 соединены параллельно
R23=(R2*R3)/(R2+R3)=(10*15)/(10+15)=150/25=6 Ом
имеем последовательное сопротивление R1,R23, R4
R=R1+R23+R4=2+6+1=9 Ом
Ответ: под буквой а) 9 Ом.
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valery00
а откуда 15?
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Answers & Comments
R23=(R2*R3)/(R2+R3)=(10*15)/(10+15)=150/25=6 Ом
имеем последовательное сопротивление R1,R23, R4
R=R1+R23+R4=2+6+1=9 Ом
Ответ: под буквой а) 9 Ом.