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annamakarovva02
@annamakarovva02
October 2021
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Задана арифметическая прогрессия. первый член равен 12, разница прогрессии равна 2. Найти сумму пятидесяти одного члена заданной прогрессии *
а 3468
б 612
в 3213
г 3162
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gnomiha211
[ an= a1+(n-1)d ]
a51=a1 + 50×2= 12+ 100 = 112
[ Sn=(a1+an)×n/2 ]
S51= (a1+a51)×(51 /2)= (12+112)×(51/2)= 124 × 51 ÷ 2 =62×51 =3162
Г
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Answers & Comments
a51=a1 + 50×2= 12+ 100 = 112
[ Sn=(a1+an)×n/2 ]
S51= (a1+a51)×(51 /2)= (12+112)×(51/2)= 124 × 51 ÷ 2 =62×51 =3162
Г