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crew52
@crew52
July 2022
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задание 19 пожалуйста)срочна надо.
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sedinalana
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3sin²π/2-4tg²π/4-3cos²π/6+3ctg²π/2=3*1²-4*1²-3*(√3/2)²+3*0²=
=3*1-4*1-3*3/4+3*0=3-4-2,25+0=-3,25
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3sin²π/2-4tg²π/4-3cos²π/6+3ctg²π/2=3*1²-4*1²-3*(√3/2)²+3*0²==3*1-4*1-3*3/4+3*0=3-4-2,25+0=-3,25