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alenafedorova
@alenafedorova
September 2021
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задание 4 срочно нужно. подробно
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miron2077
Verified answer
Написал как можно подробно
0 votes
Thanks 1
belozerova1955
1+2cosx+ cos²x sin³x
= ( ------------------------- +1) · -------------- =
sin²x 1+cosx
1+2cosx+cos²x+sin²x sin³x 2(1+cosx)·sin³x
= --------------------------------- · ----------------- = ---------------------------- =
sin²x 1+cosx sin²x·(1+cosx)
= 2sinx
0 votes
Thanks 0
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Answers & Comments
Verified answer
Написал как можно подробно= ( ------------------------- +1) · -------------- =
sin²x 1+cosx
1+2cosx+cos²x+sin²x sin³x 2(1+cosx)·sin³x
= --------------------------------- · ----------------- = ---------------------------- =
sin²x 1+cosx sin²x·(1+cosx)
= 2sinx