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lizalimon
@lizalimon
July 2022
1
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Задание 4.27. Помогите,пожалуйста)))
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sedinalana
Verified answer
11)-b/[a(a-3)(a+3)]-1/[a(a+3)]+3/[a(a-3)(a+3)]=(-b²-ab+3b+3a)/[ab(a²-9)]=
=[3(a+b)-b(a+b)]/[ab(a²-9)]=(a+b)(3-b)/[ab(a²-9)]
2)(a+b)(3-b)/[ab(a²-9)] *ab(a²-9)/(3-b)²=(a+b)/(3-b)
a=3,b=2 (3+2)/(3-1)=5/1=5
2 votes
Thanks 1
lizalimon
А можеше,пожалуйста,написать на листочке,а то так трудно понять(((
lizalimon
Sedinalana,Всё понятно)Спасибо)Только есть один вопрос: почему b²-6b+9 стало (3-b)²,а не (b-3)²?
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Answers & Comments
Verified answer
11)-b/[a(a-3)(a+3)]-1/[a(a+3)]+3/[a(a-3)(a+3)]=(-b²-ab+3b+3a)/[ab(a²-9)]==[3(a+b)-b(a+b)]/[ab(a²-9)]=(a+b)(3-b)/[ab(a²-9)]
2)(a+b)(3-b)/[ab(a²-9)] *ab(a²-9)/(3-b)²=(a+b)/(3-b)
a=3,b=2 (3+2)/(3-1)=5/1=5