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соболёчЕке
@соболёчЕке
September 2021
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задание номер 1 плиз
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nKrynka
Решение
!) f(x) = 6 / (x² - 4)
x² - 4 ≠ 0
x² ≠ 4
x1 ≠ - 2
x2 ≠ 2
D(y) = (- ∞; - 2) (-2;2) (2; + ∞)
2) f(x) = √(4x² - 1)
4x² - 1 ≥ 0
4x² ≥ 1
x² ≥ 1/4
x1 = - 1/2
x2 = 1/2
x∈(- ∞ - 1/2) (1/2; + ∞)
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Answers & Comments
!) f(x) = 6 / (x² - 4)
x² - 4 ≠ 0
x² ≠ 4
x1 ≠ - 2
x2 ≠ 2
D(y) = (- ∞; - 2) (-2;2) (2; + ∞)
2) f(x) = √(4x² - 1)
4x² - 1 ≥ 0
4x² ≥ 1
x² ≥ 1/4
x1 = - 1/2
x2 = 1/2
x∈(- ∞ - 1/2) (1/2; + ∞)