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logik444
@logik444
November 2021
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Задание в приложении , 50 баллов.
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alvardsaroyan
(x₁-x₀)(x₂`-x₀`)=(x₂-x₀)(x₁-x₀`)
x₁x₂`-x₁x₀`-x₀x₂`+x₀x₀`=x₁x₂-x₂x₀`-x₁x₀+x₀x₀`
x₁x₂`-x₁x₀`-x₀x₂`-x₁x₂+x₂x₀`+x₁x₀=0
x₂x₀`-x₁x₀`=-x₁x₂`+x₀x₂`+x₁x₂-x₁x₀
x₀`(x₂-x₁)=-x₁x₂`+x₀x₂`+x₁x₂-x₁x₀
x₀`=(-x₁x₂`+x₀x₂`+x₁x₂-x₁x₀)/(x₂-x₁)
1 votes
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logik444
Спасибо)
alvardsaroyan
ok
julyap
2 votes
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Answers & Comments
x₁x₂`-x₁x₀`-x₀x₂`+x₀x₀`=x₁x₂-x₂x₀`-x₁x₀+x₀x₀`
x₁x₂`-x₁x₀`-x₀x₂`-x₁x₂+x₂x₀`+x₁x₀=0
x₂x₀`-x₁x₀`=-x₁x₂`+x₀x₂`+x₁x₂-x₁x₀
x₀`(x₂-x₁)=-x₁x₂`+x₀x₂`+x₁x₂-x₁x₀
x₀`=(-x₁x₂`+x₀x₂`+x₁x₂-x₁x₀)/(x₂-x₁)